[+] A1 P1 Q1 Implement the 3 Heuristics

This commit is contained in:
MstrPikachu
2022-01-22 21:20:35 -05:00
parent 820d1b0d97
commit 85d6e3ac3d
+69
View File
@@ -47,6 +47,20 @@ class MoveToFrontLinkedList(LinkedList):
>>> linky.to_list()
[40, 10, 20, 30, 50, 60]
"""
if not self._first:
return False
if self._first.item == item:
return True
cur = self._first
while cur.next:
if cur.next.item == item: # found
cur.next = cur.next.next # delete
node = _Node(item, self._first)
self._first = node # insert to front
return True
cur = cur.next
return False
################################################################################
@@ -70,6 +84,19 @@ class SwapLinkedList(LinkedList):
>>> linky.to_list()
[10, 20, 40, 30, 50, 60]
"""
if not self._first:
return False
if self._first.item == item:
return True
cur = self._first
while cur.next:
if cur.next.item == item: # found
temp = cur.item # swap
cur.item = cur.next.item
cur.next.item = temp
return True
cur = cur.next
return False
################################################################################
@@ -114,6 +141,48 @@ class CountLinkedList(LinkedList):
>>> linky.to_list()
[40, 10, 20, 30, 50, 60]
"""
if not self._first:
return False
if self._first.item == item:
self._first.access_count += 1
return True
count = 0
cur = self._first
while cur.next:
if cur.next.item == item:
count = cur.next.access_count + 1
cur.next = cur.next.next # delete node
break # break to prevent huge nesting
cur = cur.next
if count == 0: # not found
return False
if count > self._first.access_count:
node = _CountNode(item, self._first, count)
self._first = node # insert to front
return True
cur = self._first
while (not cur.next) or cur.next.access_count < count:
cur = cur.next
cur.next = _CountNode(item, cur.next.next, count) # insert node
def append(self, item: Any) -> None:
"""Add the given item to the end of this linked list.
"""
new_node = _CountNode(item, None, 0)
if self._first is None:
self._first = new_node
else:
curr = self._first
while curr.next is not None:
curr = curr.next
# After the loop, curr is the last node in the LinkedList.
assert curr is not None and curr.next is None
curr.next = new_node
if __name__ == '__main__':