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[JVM] Don't analyze KtCodeFragment's file twice

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We could get several files from the IDE to analyze. For example, some
code fragment and a file with context information. This additional
file, in fact, can be a file where a code fragment is defined, and we
can accidentally analyze a single file twice that leads to errors.
This commit is contained in:
Ivan Kylchik
2023-10-24 18:29:54 +02:00
committed by Space Team
parent d6f0530215
commit d7d42134df
1 changed files with 10 additions and 9 deletions
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compiler/backend/src/org/jetbrains/kotlin/codegen/binding/CodegenBinding.java
+10 -9
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@@ -30,6 +30,8 @@ import org.jetbrains.kotlin.utils.KotlinExceptionWithAttachments;
import org.jetbrains.org.objectweb.asm.Type;
import java.util.*;
import java.util.stream.Collectors;
import java.util.stream.Stream;
import static org.jetbrains.kotlin.resolve.BindingContext.*;
@@ -96,15 +98,14 @@ public class CodegenBinding {
public static void initTrace(@NotNull GenerationState state, Collection<KtFile> files) {
CodegenAnnotatingVisitor visitor = new CodegenAnnotatingVisitor(state);
for (KtFile file : allFilesInPackages(state.getBindingContext(), files)) {
file.accept(visitor);
if (file instanceof KtCodeFragment) {
PsiFile contextFile = ((KtCodeFragment) file).getContextContainingFile();
if (contextFile != null) {
contextFile.accept(visitor);
}
}
}
Collection<KtFile> allFiles = allFilesInPackages(state.getBindingContext(), files);
Stream<PsiFile> codeFragmentFiles = allFiles.stream()
.filter(file -> file instanceof KtCodeFragment)
.map(file -> {
PsiFile contextFile = ((KtCodeFragment) file).getContextContainingFile();
return contextFile != null ? contextFile : file;
});
Stream.concat(allFiles.stream(), codeFragmentFiles).distinct().forEach(file -> file.accept(visitor));
}
public static boolean enumEntryNeedSubclass(BindingContext bindingContext, KtEnumEntry enumEntry) {