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Fix bug when string representation of flexible kt type was wrong

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This commit is contained in:
Vitaliy.Bibaev
2017-11-21 19:21:51 +03:00
committed by Yan Zhulanow
parent 8900411fb1
commit 5a02f37d1f
1 changed files with 10 additions and 3 deletions
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idea/idea-jvm/src/com/intellij/debugger/streams/kotlin/psi/KotlinPsiUtil.kt
+10 -3
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@@ -2,14 +2,15 @@
package com.intellij.debugger.streams.kotlin.psi
import org.jetbrains.kotlin.idea.caches.resolve.analyze
import org.jetbrains.kotlin.idea.util.approximateFlexibleTypes
import org.jetbrains.kotlin.psi.KtCallExpression
import org.jetbrains.kotlin.psi.KtDotQualifiedExpression
import org.jetbrains.kotlin.psi.KtExpression
import org.jetbrains.kotlin.renderer.DescriptorRenderer
import org.jetbrains.kotlin.renderer.DescriptorRendererModifier
import org.jetbrains.kotlin.resolve.calls.callUtil.getResolvedCall
import org.jetbrains.kotlin.resolve.descriptorUtil.fqNameSafe
import org.jetbrains.kotlin.resolve.scopes.receivers.ReceiverValue
import org.jetbrains.kotlin.types.FlexibleType
import org.jetbrains.kotlin.types.KotlinType
/**
@@ -17,9 +18,15 @@ import org.jetbrains.kotlin.types.KotlinType
*/
object KotlinPsiUtil {
private val WITH_TYPES_RENDERER = DescriptorRenderer.withOptions { modifiers = DescriptorRendererModifier.ALL }
private val WITH_TYPES_RENDERER = DescriptorRenderer.FQ_NAMES_IN_TYPES
fun getTypeName(type: KotlinType): String = WITH_TYPES_RENDERER.renderType(type)
fun getTypeName(type: KotlinType): String {
if (type is FlexibleType) {
return WITH_TYPES_RENDERER.renderType(type.approximateFlexibleTypes())
}
return WITH_TYPES_RENDERER.renderType(type)
}
fun getTypeWithoutTypeParameters(type: KotlinType): String {
val descriptor = type.constructor.declarationDescriptor ?: return getTypeName(type)