Don't enclose 'this' in braces inside string templates

This commit is contained in:
Dmitry Jemerov
2018-01-11 18:46:50 +01:00
parent 560dc920e4
commit 0b24be9460
@@ -1,17 +1,6 @@
/*
* Copyright 2010-2015 JetBrains s.r.o.
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
* Copyright 2000-2018 JetBrains s.r.o. Use of this source code is governed by the Apache 2.0 license
* that can be found in the license/LICENSE.txt file.
*/
package org.jetbrains.kotlin.psi
@@ -45,7 +34,7 @@ abstract class KtExpressionImpl(node: ASTNode) : KtElementImpl(node), KtExpressi
}
}
is KtSimpleNameStringTemplateEntry -> {
if (newElement !is KtSimpleNameExpression) {
if (newElement !is KtSimpleNameExpression && !newElement.isThisWithoutLabel()) {
val newEntry = parent.replace(KtPsiFactory(expression).createBlockStringTemplateEntry(newElement)) as KtBlockStringTemplateEntry
return newEntry.expression!!
}
@@ -57,3 +46,5 @@ abstract class KtExpressionImpl(node: ASTNode) : KtElementImpl(node), KtExpressi
}
}
}
private fun PsiElement.isThisWithoutLabel() = this is KtThisExpression && getLabelName() == null