Don't enclose 'this' in braces inside string templates
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@@ -1,17 +1,6 @@
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/*
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* Copyright 2010-2015 JetBrains s.r.o.
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*
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* Licensed under the Apache License, Version 2.0 (the "License");
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* you may not use this file except in compliance with the License.
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* You may obtain a copy of the License at
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*
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* http://www.apache.org/licenses/LICENSE-2.0
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*
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* Unless required by applicable law or agreed to in writing, software
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* distributed under the License is distributed on an "AS IS" BASIS,
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* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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* See the License for the specific language governing permissions and
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* limitations under the License.
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* Copyright 2000-2018 JetBrains s.r.o. Use of this source code is governed by the Apache 2.0 license
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* that can be found in the license/LICENSE.txt file.
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*/
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package org.jetbrains.kotlin.psi
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@@ -45,7 +34,7 @@ abstract class KtExpressionImpl(node: ASTNode) : KtElementImpl(node), KtExpressi
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}
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}
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is KtSimpleNameStringTemplateEntry -> {
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if (newElement !is KtSimpleNameExpression) {
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if (newElement !is KtSimpleNameExpression && !newElement.isThisWithoutLabel()) {
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val newEntry = parent.replace(KtPsiFactory(expression).createBlockStringTemplateEntry(newElement)) as KtBlockStringTemplateEntry
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return newEntry.expression!!
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}
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@@ -57,3 +46,5 @@ abstract class KtExpressionImpl(node: ASTNode) : KtElementImpl(node), KtExpressi
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}
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}
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}
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private fun PsiElement.isThisWithoutLabel() = this is KtThisExpression && getLabelName() == null
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