Finish Part3 Q2b
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MstrPikachu
+67
-63
@@ -139,87 +139,91 @@ def is_valid(schedule: dict[str, tuple[str, str, tuple]]) -> bool:
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def possible_schedules(c1: tuple[str, str, set], c2: tuple[str, str, set]) \
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-> list[dict[str, tuple[str, str, tuple]]]:
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"""Return a list of all possible schedules of courses c1 and c2.
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-> list[dict[str, tuple[str, str, tuple]]]:
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"""Return a list of all possible schedules of courses c1 and c2.
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Each returned schedule should contain exactly two key-value pairs, one with the course
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code and a section of c1, and the other with the course code and a section of c2.
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Each returned schedule should contain exactly two key-value pairs, one with the course
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code and a section of c1, and the other with the course code and a section of c2.
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Invalid schedules are returned in this list.
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Invalid schedules are returned in this list.
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If a given course has no sections, then return an empty list.
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(This will happen "automatically" if you use a comprehension with an empty collection!)
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If a given course has no sections, then return an empty list.
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(This will happen "automatically" if you use a comprehension with an empty collection!)
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Preconditions:
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- c1 and c2 match the format for a course described by the assignment handout.
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- c1 != c2
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"""
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Preconditions:
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- c1 and c2 match the format for a course described by the assignment handout.
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- c1 != c2
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"""
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return [{c1[0]: section1, c2[0]: section2} for section1 in c1[2] for section2 in c2[2]]
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def valid_schedules(c1: tuple[str, str, set],
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c2: tuple[str, str, set]) \
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-> list[dict[str, tuple[str, str, tuple]]]:
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"""Return a list of all VALID schedules of courses c1 and c2.
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def valid_schedules(c1: tuple[str, str, set],
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c2: tuple[str, str, set]) \
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-> list[dict[str, tuple[str, str, tuple]]]:
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"""Return a list of all VALID schedules of courses c1 and c2.
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Each returned schedule should contain exactly two key-value pairs, one with the course
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code and a section of c1, and the other with the course code and a section of c2.
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Each returned schedule should contain exactly two key-value pairs, one with the course
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code and a section of c1, and the other with the course code and a section of c2.
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Invalid schedules are NOT returned in this list.
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Invalid schedules are NOT returned in this list.
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Hint:
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- Use is_valid
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- Use possible_schedules
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Hint:
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- Use is_valid
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- Use possible_schedules
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Preconditions:
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- c1 and c2 match the format for a course described by the assignment handout.
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- c1 != c2
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"""
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schedules = possible_schedules(c1, c2)
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return [x for x in schedules if is_valid(x)]
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Preconditions:
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- c1 and c2 match the format for a course described by the assignment handout.
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- c1 != c2
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"""
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def possible_five_course_schedules(c1: tuple[str, str, set],
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c2: tuple[str, str, set],
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c3: tuple[str, str, set],
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c4: tuple[str, str, set],
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c5: tuple[str, str, set]) -> list[dict[str, tuple]]:
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"""Return a list of every possible schedule that contains all given courses.
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This is analogous to possible_schedules, except now there are 5 courses instead of 2.
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def possible_five_course_schedules(c1: tuple[str, str, set],
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c2: tuple[str, str, set],
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c3: tuple[str, str, set],
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c4: tuple[str, str, set],
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c5: tuple[str, str, set]) -> list[dict[str, tuple]]:
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"""Return a list of every possible schedule that contains all given courses.
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If a given course has no sections, then return an empty list.
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(This will happen "automatically" if you use a comprehension with an empty collection!)
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This is analogous to possible_schedules, except now there are 5 courses instead of 2.
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Preconditions:
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- all given courses match the format for a course described by the assignment handout.
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- c1 != c2 and c1 != c3 and c1 != c4 and c1 != c5
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- c2 != c3 and c2 != c4 and c2 != c5
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- c3 != c4 and c3 != c5
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- c4 != c5
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If a given course has no sections, then return an empty list.
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(This will happen "automatically" if you use a comprehension with an empty collection!)
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HINT: you'll want a comprehension with 5 different variables. You can split up each
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"for ... in ..." across multiple lines to help make your code more readable.
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"""
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return [{c1[0]: a, c2[0]: b, c3[0]: c, c4[0]: d, c5[0]: e} for a in c1[2] for b in c2[2] for c in c3[2] for d in
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c4[2] for e in c5[2]]
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Preconditions:
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- all given courses match the format for a course described by the assignment handout.
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- c1 != c2 and c1 != c3 and c1 != c4 and c1 != c5
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- c2 != c3 and c2 != c4 and c2 != c5
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- c3 != c4 and c3 != c5
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- c4 != c5
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def valid_five_course_schedules(c1: tuple[str, str, set],
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c2: tuple[str, str, set],
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c3: tuple[str, str, set],
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c4: tuple[str, str, set],
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c5: tuple[str, str, set]) -> list[dict[str, tuple]]:
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"""Return a list of every valid schedule that contains all given courses.
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HINT: you'll want a comprehension with 5 different variables. You can split up each
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"for ... in ..." across multiple lines to help make your code more readable.
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"""
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This is analogous to valid_schedules, except now there are 5 courses instead of 2.
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Hint:
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- Use is_valid
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- Use possible_five_course_schedules
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def valid_five_course_schedules(c1: tuple[str, str, set],
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c2: tuple[str, str, set],
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c3: tuple[str, str, set],
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c4: tuple[str, str, set],
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c5: tuple[str, str, set]) -> list[dict[str, tuple]]:
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"""Return a list of every valid schedule that contains all given courses.
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This is analogous to valid_schedules, except now there are 5 courses instead of 2.
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Hint:
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- Use is_valid
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- Use possible_five_course_schedules
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Preconditions:
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- all given courses match the format for a course described by the assignment handout.
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- c1 != c2 and c1 != c3 and c1 != c4 and c1 != c5
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- c2 != c3 and c2 != c4 and c2 != c5
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- c3 != c4 and c3 != c5
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- c4 != c5
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"""
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Preconditions:
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- all given courses match the format for a course described by the assignment handout.
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- c1 != c2 and c1 != c3 and c1 != c4 and c1 != c5
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- c2 != c3 and c2 != c4 and c2 != c5
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- c3 != c4 and c3 != c5
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- c4 != c5
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"""
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schedules = possible_five_course_schedules(c1, c2, c3, c4, c5)
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return [x for x in schedules if is_valid(x)]
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###################################################################################################
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