Ivan Kylchik
4f15bd4817
There is a problem with ranges and iterators. To work properly they must be resolved firstly, before operator rangeTo.
41 lines
1.6 KiB
Kotlin
Vendored
41 lines
1.6 KiB
Kotlin
Vendored
// this hack is used to ensure that iterator will be resolved first
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@CompileTimeCalculation internal class IntProgressionIterator(first: Int, last: Int, val step: Int) : IntIterator()
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@CompileTimeCalculation public class IntRange(start: Int, endInclusive: Int) : IntProgression(start, endInclusive, 1), ClosedRange<Int>
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@CompileTimeCalculation
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fun varargSum(quantityToSum: Int, vararg num: Int): Int {
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var sum = 0
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for (i in 0..(quantityToSum - 1)) {
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if (i >= num.size) return sum
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sum += num[i]
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}
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return sum
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}
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@CompileTimeCalculation
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fun sumWithVarargAtFirst(vararg num: Int, quantityToSum: Int = num.size) = varargSum(quantityToSum, *num)
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@CompileTimeCalculation
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fun concatenation(vararg str: String): String {
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var result = ""
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for (s in str) result += s
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return result
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}
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@CompileTimeCalculation
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fun customArrayConcatenation(vararg array: Any?): String {
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var result = ""
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for (elem in array) result += elem.toString() + " "
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return result
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}
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const val a1 = <!EVALUATED: `6`!>varargSum(3, 1, 2, 3)<!>
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const val a2 = <!EVALUATED: `3`!>varargSum(num = *intArrayOf(1, 2, 3), quantityToSum = 2)<!>
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const val a3 = <!EVALUATED: `21`!>varargSum(6, *intArrayOf(1, 2), 3, *intArrayOf(4, 5, 6))<!>
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const val b1 = <!EVALUATED: `6`!>sumWithVarargAtFirst(1, 2, 3)<!>
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const val b2 = <!EVALUATED: `6`!>sumWithVarargAtFirst(quantityToSum = 3, num = *intArrayOf(1, 2, 3))<!>
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const val c1 = <!EVALUATED: `1 2 3`!>concatenation(*arrayOf("1", " "), "2", *arrayOf(" ", "3"))<!>
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const val c2 = <!EVALUATED: `1 2.0 3 -1 -2.0 `!>customArrayConcatenation(*arrayOf(1, 2.0), "3", *arrayOf(-1, -2.0))<!>
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