Dmitriy Novozhilov
88a1cb5a17
It's necessary because of new type substitutor is eager than odl, so if there is a substitution of type parameter deep inside type arguments then second substitutor wins against first #KT-35896 Fixed
25 lines
1.1 KiB
Plaintext
Vendored
25 lines
1.1 KiB
Plaintext
Vendored
package
|
|
|
|
public fun </*0*/ T1, /*1*/ T2, /*2*/ S> bar(/*0*/ list: T2, /*1*/ fn: (S) -> B<T1, T2>): kotlin.Unit
|
|
public fun </*0*/ K> foo(/*0*/ list: Inv<K>): kotlin.Unit
|
|
|
|
public interface B</*0*/ E, /*1*/ SC> {
|
|
public open override /*1*/ /*fake_override*/ fun equals(/*0*/ other: kotlin.Any?): kotlin.Boolean
|
|
public open override /*1*/ /*fake_override*/ fun hashCode(): kotlin.Int
|
|
public open override /*1*/ /*fake_override*/ fun toString(): kotlin.String
|
|
}
|
|
|
|
public final class Foo</*0*/ T> : B<T, Inv<T>> {
|
|
public constructor Foo</*0*/ T>(/*0*/ x: kotlin.Int)
|
|
public open override /*1*/ /*fake_override*/ fun equals(/*0*/ other: kotlin.Any?): kotlin.Boolean
|
|
public open override /*1*/ /*fake_override*/ fun hashCode(): kotlin.Int
|
|
public open override /*1*/ /*fake_override*/ fun toString(): kotlin.String
|
|
}
|
|
|
|
public final class Inv</*0*/ T> {
|
|
public constructor Inv</*0*/ T>()
|
|
public open override /*1*/ /*fake_override*/ fun equals(/*0*/ other: kotlin.Any?): kotlin.Boolean
|
|
public open override /*1*/ /*fake_override*/ fun hashCode(): kotlin.Int
|
|
public open override /*1*/ /*fake_override*/ fun toString(): kotlin.String
|
|
}
|