Brian Norman
ccda8ae23d
When the left-hand side of an equality comparison is known to be a String, and the equality condition resolves to true, then the right-hand side can be smart-cast to a String as well. This was working for String expressions on the left-hand side but not for String constants. ^KT-57513 Fixed
25 lines
1.1 KiB
Plaintext
Vendored
25 lines
1.1 KiB
Plaintext
Vendored
package
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public fun bar(/*0*/ i: Test?): kotlin.Unit
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public fun bar(/*0*/ i: TestWithEquals?): kotlin.Unit
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public fun char(/*0*/ foo: kotlin.Any): kotlin.Unit
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public fun foo(/*0*/ x: kotlin.String?): kotlin.String?
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public fun gav(/*0*/ i: TestWithEquals?, /*1*/ j: TestWithEquals?): kotlin.Unit
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public fun int(/*0*/ foo: kotlin.Any): kotlin.Unit
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public fun long(/*0*/ foo: kotlin.Any): kotlin.Unit
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public fun string(/*0*/ foo: kotlin.Any): kotlin.Unit
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public final class Test {
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public constructor Test()
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public open override /*1*/ /*fake_override*/ fun equals(/*0*/ other: kotlin.Any?): kotlin.Boolean
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public open override /*1*/ /*fake_override*/ fun hashCode(): kotlin.Int
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public open override /*1*/ /*fake_override*/ fun toString(): kotlin.String
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}
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public final class TestWithEquals {
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public constructor TestWithEquals()
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public open override /*1*/ fun equals(/*0*/ other: kotlin.Any?): kotlin.Boolean
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public open override /*1*/ /*fake_override*/ fun hashCode(): kotlin.Int
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public open override /*1*/ /*fake_override*/ fun toString(): kotlin.String
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}
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