58b815d842
Note that current behaviour is made similar to the case with properties initializers/accessors, which means that more complex cases are not covered yet (see KT-20801) #KT-20802 fixed.
12 lines
380 B
Kotlin
Vendored
12 lines
380 B
Kotlin
Vendored
fun <T> id(x: T): T = x
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fun foo() = 1 as Any
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fun bar() = id(1) as Any
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fun baz() = (1 + 1) as Any
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val functionLiteral1 = fun() = 1 as Any
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val functionLiteral2 = fun() = id(1) as Any
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val functionLiteral3 = fun() = (1 + 1) as Any
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// TODO: this and more complex cases are not supported yet
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fun baz(b: Boolean) = if (b) 1 <!USELESS_CAST!>as Any<!> else 42 <!USELESS_CAST!>as Any?<!> |