Brian Norman
ccda8ae23d
When the left-hand side of an equality comparison is known to be a String, and the equality condition resolves to true, then the right-hand side can be smart-cast to a String as well. This was working for String expressions on the left-hand side but not for String constants. ^KT-57513 Fixed
54 lines
1.5 KiB
Kotlin
Vendored
54 lines
1.5 KiB
Kotlin
Vendored
fun foo(x: String?) = x
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class Test
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class TestWithEquals {
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override fun equals(other: Any?) = super.equals(other)
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}
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fun bar(i: Test?) {
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if (i == null) foo(<!DEBUG_INFO_CONSTANT!>i<!>)
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}
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fun bar(i: TestWithEquals?) {
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if (i == null) foo(<!DEBUG_INFO_CONSTANT!>i<!>)
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if (null == i) foo(<!DEBUG_INFO_CONSTANT!>i<!>)
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when (i) {
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null -> foo(<!DEBUG_INFO_CONSTANT!>i<!>)
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}
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}
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fun gav(i: TestWithEquals?, j: TestWithEquals?) {
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if (j == null) {
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if (i == <!DEBUG_INFO_CONSTANT!>j<!>) foo(<!DEBUG_INFO_CONSTANT!>i<!>)
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}
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}
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fun string(foo: Any) {
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val string = ""
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if ("" == foo) <!DEBUG_INFO_SMARTCAST!>foo<!>.length
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if (string == foo) <!DEBUG_INFO_SMARTCAST!>foo<!>.length
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if (foo == "") foo.<!UNRESOLVED_REFERENCE!>length<!>
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}
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fun int(foo: Any) {
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val int = 1
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if (1 == foo) foo.<!UNRESOLVED_REFERENCE_WRONG_RECEIVER!>plus<!>(1)
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if (int == foo) foo.<!UNRESOLVED_REFERENCE_WRONG_RECEIVER!>plus<!>(1)
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if (foo == 1) foo.<!UNRESOLVED_REFERENCE_WRONG_RECEIVER!>plus<!>(1)
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}
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fun long(foo: Any) {
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val long = 1L
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if (1L == foo) foo.<!UNRESOLVED_REFERENCE_WRONG_RECEIVER!>plus<!>(1L)
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if (long == foo) foo.<!UNRESOLVED_REFERENCE_WRONG_RECEIVER!>plus<!>(1L)
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if (foo == 1L) foo.<!UNRESOLVED_REFERENCE_WRONG_RECEIVER!>plus<!>(1L)
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}
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fun char(foo: Any) {
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val char = 'a'
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if ('a' == foo) foo.<!UNRESOLVED_REFERENCE!>compareTo<!>('a')
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if (char == foo) foo.<!UNRESOLVED_REFERENCE!>compareTo<!>('a')
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if (foo == 'a') foo.<!UNRESOLVED_REFERENCE!>compareTo<!>('a')
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}
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