f5a086140e
Generate special bridge even in case current class has Kotlin superclass implementing this builtin method, but that super class was generated without special bridge (e.g. because it would have the same signature) #KT-9901 Fixed
59 lines
1.5 KiB
Kotlin
Vendored
59 lines
1.5 KiB
Kotlin
Vendored
var result = ""
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public abstract class AbstractFoo<K, V> : Map<K, V> {
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override operator fun get(key: K): V? {
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result = "AbstractFoo"
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return null
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}
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override val size: Int
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get() = throw UnsupportedOperationException()
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override fun isEmpty(): Boolean {
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throw UnsupportedOperationException()
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}
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override fun containsKey(key: K): Boolean {
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throw UnsupportedOperationException()
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}
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override fun containsValue(value: V): Boolean {
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throw UnsupportedOperationException()
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}
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override val keys: Set<K>
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get() = throw UnsupportedOperationException()
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override val values: Collection<V>
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get() = throw UnsupportedOperationException()
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override val entries: Set<Map.Entry<K, V>>
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get() = throw UnsupportedOperationException()
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}
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public open class StringFoo<E> : AbstractFoo<String, E>() {
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override operator fun get(key: String): E? {
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result = "StringFoo"
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return null
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}
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}
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public class IntFoo<E> : AbstractFoo<Int, E>() {
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override operator fun get(key: Int): E? {
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result = "IntFoo"
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return null
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}
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}
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public class AnyFoo<E> : AbstractFoo<Any?, E>() {}
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fun box(): String {
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StringFoo<String>().get("")
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if (result != "StringFoo") return "fail 1: $result"
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IntFoo<String>().get(1)
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if (result != "IntFoo") return "fail 2: $result"
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AnyFoo<String>().get(null)
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if (result != "AbstractFoo") return "fail 3: $result"
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return "OK"
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} |