Dmitry Petrov
495fba43c0
In code like 'a?.b == 42', we can immediately generate equality comparison result when receiver is null (false for '==', true for '!='), since the primitive value is definitely non-null. Otherwise unnecessary boxing/unboxing is generated to handle possibly null result of 'a?.b'.
43 lines
948 B
Kotlin
Vendored
43 lines
948 B
Kotlin
Vendored
fun Long.id() = this
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fun String.drop2() = if (length >= 2) subSequence(2, length) else null
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fun String.anyLength(): Any = length
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fun doSimple(s: String?) = s?.length != 3
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fun doLongReceiver(x: Long) = x?.id() != 3L
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fun doChain(s: String?) = s?.drop2()?.length != 1
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fun doIf(s: String?) =
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if (s?.length != 1) "A" else "B"
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fun doCmpWithAny(s: String?) =
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s?.anyLength() != 3
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fun box(): String = when {
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!doSimple(null) -> "failed 1"
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!doSimple("1") -> "failed 2"
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doSimple("123") -> "failed 3"
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!doLongReceiver(2L) -> "failed 4"
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doLongReceiver(3L) -> "failed 5"
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!doChain(null) -> "failed 6"
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!doChain("1") -> "failed 7"
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doChain("123") -> "failed 7"
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doIf("1") == "A" -> "failed 8"
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doIf("123") == "B" -> "failed 9"
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doIf(null) == "B" -> "failed 10"
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!doCmpWithAny(null) -> "failed 11"
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!doCmpWithAny("1") -> "failed 12"
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doCmpWithAny("123") -> "failed 13"
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else -> "OK"
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} |