d2fcd71d23
If you want to shorten call like `foo.bar()` into `bar()`, then you need your range to intersect with `bar` callee reference. Having only `foo` in the range is not enough Same goes for the type references - to shorten `foo.Bar` into `Bar`, you need at least some intersection of your range with `Bar` reference ^KTIJ-27139 Fixed ^KTIJ-27015 Fixed