Mikhail Zarechenskiy
617bed1bf1
Consider the following situation: ``` class Inv<T> typealias A<K> = Inv<K> typealias B<V> = Inv<A<K>> fun <U> materialize(): B<U> = TODO() ``` Type `B<U>` is expanding to `Inv<Inv<U>>` and for this type `B<U>` and `Inv<A<U>>` are abbreviated types, but due to a bug we forgot to make substitution for `Inv<A<U>>` and were getting abbreviated type `Inv<A<K>>` where `K` is a type parameter from the typealias declaration. This bug didn't affect subtyping anyhow but the incorrect type was serialized and caused problems during deserialization as there wasn't `K` in deserialization context. #KT-24964 Fixed #KT-20780 Fixed #KT-20065 Fixed #KT-28236 Fixed #KT-21775 Fixed
43 lines
760 B
Kotlin
Vendored
43 lines
760 B
Kotlin
Vendored
// FILE: lib.kt
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package lib
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class TestObserver<T> {
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fun assertValue(valuePredicate: (T) -> Boolean): Unit = TODO()
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}
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class Single<T> {
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fun test(): TestObserver<T> = TODO()
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}
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class Employee
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class Either<T>
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typealias DomainEither<T> = Either<T>
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typealias DomainSingle<T> = Single<DomainEither<T>>
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fun provideDomainSingle(): DomainSingle<Employee> = TODO()
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class CreateEmployeeUseCaseAccessor {
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fun testNormalName() {
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val testObs = provideDomainSingle().test()
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testObs.assertValue { true }
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}
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}
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// FILE: main.kt
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import lib.*
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class CreateEmployeeUseCaseTest {
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fun testNormalName() {
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val testObs = provideDomainSingle().test()
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testObs.assertValue { true }
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}
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}
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fun box(): String {
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return "OK"
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} |