Dmitry Petrov
2f82c5b6af
When we generate call for 'foo', we make decision about invoking a 'foo$default' too late, after the call arguments are generated. If 'foo' was an override, and base class (interface) was generic, 'foo' in base class could have a different Kotlin and JVM signature, so the arguments we generated could be generated wrong (primitive or inline class values instead of boxes, see KT-38680). Also, we always selected first base class in supertypes list, which caused KT-15971. Look into resolved call and see if we should actually call 'foo$default' instead of 'foo' when determining actual callable. Overrides can't introduce default parameter values, and override-equivalent inherited methods with default parameters is an error in a child class. Thus, if we are calling a class member function with a default parameters, there should be one and only one overridden function that has default parameter values and overrides nothing.
60 lines
989 B
Kotlin
Vendored
60 lines
989 B
Kotlin
Vendored
// IGNORE_BACKEND_FIR: JVM_IR
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var log = ""
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fun log(a: String) {
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log += a + ";"
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}
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interface C {
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fun foo(x: Int): Unit {
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log("C.foo($x)")
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}
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}
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interface I {
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fun foo(x: Int = 1): Unit
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}
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class G(c: C) : C by c, I
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class H(c: C) : I, C by c
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fun test1() {
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log = ""
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val g1 = G(object: C {})
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g1.foo(2)
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g1.foo()
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val g2 = G(object: C {
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override fun foo(x: Int) {
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log("[2] object:C.foo($x)")
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}
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})
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g2.foo(2)
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g2.foo()
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}
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fun test2() {
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log = ""
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val h1 = H(object: C {})
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h1.foo(2)
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h1.foo()
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val h2 = H(object: C {
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override fun foo(x: Int) {
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log("[2] object:C.foo($x)")
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}
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})
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h2.foo(2)
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h2.foo()
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}
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fun box(): String {
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test1()
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if (log != "C.foo(2);C.foo(1);[2] object:C.foo(2);[2] object:C.foo(1);") return "fail1: $log"
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test2()
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if (log != "C.foo(2);C.foo(1);[2] object:C.foo(2);[2] object:C.foo(1);") return "fail2: $log"
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return "OK"
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} |