Alexander Udalov
66e19b13ce
This is possible when a lambda's contract guarantees initialization of a variable.
22 lines
509 B
Kotlin
Vendored
22 lines
509 B
Kotlin
Vendored
// !LANGUAGE: +AllowContractsForCustomFunctions +UseCallsInPlaceEffect +ReadDeserializedContracts
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// !USE_EXPERIMENTAL: kotlin.contracts.ExperimentalContracts
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// IGNORE_BACKEND: NATIVE
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import kotlin.contracts.*
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@Suppress("INVISIBLE_MEMBER", "INVISIBLE_REFERENCE")
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public fun myrun(block: () -> Unit) {
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contract {
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callsInPlace(block, InvocationKind.EXACTLY_ONCE)
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}
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block()
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}
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fun box(): String {
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val x: Long
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myrun {
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x = 1L
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}
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return if (x != 1L) "FAIL" else "OK"
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}
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