Dmitriy Novozhilov
d4f55894b4
If some function is not fake-override, then its type should be just default type of containing class For fake overrides the default type calculated in the following way: 1. Find first overridden function, which is not fake override 2. Take its containing class 3. Find supertype of current containing class with type constructor of class from step 2 ^KT-60252 Fixed
41 lines
511 B
Kotlin
Vendored
41 lines
511 B
Kotlin
Vendored
open class A<A_T : Any?> {
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constructor() /* primary */ {
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super/*Any*/()
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/* <init>() */
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}
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}
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open class B<B_T : Any?> : A<B_T> {
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constructor() /* primary */ {
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super/*A*/<B_T>()
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/* <init>() */
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}
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override fun hashCode(): Int {
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return 0
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}
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}
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open class C<C_T : Any?> : B<C_T> {
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constructor() /* primary */ {
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super/*B*/<C_T>()
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/* <init>() */
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}
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}
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open class D<D_T : Any?> : C<D_T> {
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constructor() /* primary */ {
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super/*C*/<D_T>()
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/* <init>() */
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}
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}
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