Tianyu Geng
d3c91ee9be
That is, for a labeled `super`, the keyword should resolve to the super type and the label should be resolved to the current type.
8 lines
99 B
Kotlin
Vendored
8 lines
99 B
Kotlin
Vendored
interface A {
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fun a() {}
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}
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class Foo : A {
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fun foo() {
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super@F<caret>oo.a()
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}
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} |