Denis Zharkov
f1026935a0
If property name is parsed on the next line and declaration is invalid (no receiver/type/initializer), treat that name as it does not belong to property #KT-12987 In Progress
42 lines
497 B
Kotlin
Vendored
42 lines
497 B
Kotlin
Vendored
fun foo() {
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val
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println("abc")
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val
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lambdaCall {
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}
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val
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if (1 == 1) {
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}
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val
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(1 + 2)
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// `propertyNameOnTheNextLine` parsed as simple name expression
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val
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propertyNameOnTheNextLine
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val
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// comment
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propertyNameOnTheNextLine
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val /* comment */
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propertyNameOnTheNextLine
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// Correct properties
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val
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property1 = 1
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val
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propertyWithBy by lazy { 1 }
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val
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propertyWithType: Int
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val
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(a, b) = 1
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}
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