We have an invariant that their lower bound is always
SomeType<Any?> and their upper bound is SomeType<*>.
Ehancing the latter to SomeType<out Any> making
lower bound not being a subtype of upper bound that breaks contract
for flexible types (fails with exception)
If there is default qualifier with TYPE_USE closer than one with METHOD
then its nullability should be considered even when enhancing return type
#KT-20016 Fixed
- Apply default qualifiers to type arguments if they contain TYPE_USE
in applicability list
- Read TYPE_USE placed default qualifier annotations
#KT-19592 Fixed
#KT-20016 In Progress
Denis Zharkov