properly read vararg signature from java code
KT-1694 Java vararg override, Why is it intuitive interface? #KT-1694 Fixed
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// FILE: Aaa.java
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// http://youtrack.jetbrains.com/issue/KT-1694
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public abstract class Aaa {
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public abstract void foo(String... args);
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}
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// FILE: bbb.kt
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class Bbb() : Aaa() {
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override fun foo(vararg args: String?) = #()
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}
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