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Don't look at raw type's arguments while enhancing super types

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^KT-48172 Fixed
This commit is contained in:
Victor Petukhov
2021-08-17 18:41:34 +03:00
committed by TeamCityServer
parent 63cefe228d
commit d730db094a
14 changed files with 188 additions and 33 deletions
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compiler/testData/loadJava/compiledJava/signaturePropagation/RawSuperTypeWithRecursiveBound.txt
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+1 -1
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@@ -3,7 +3,7 @@ package test
public open class RawSuperTypeWithRecursiveBound {
public constructor RawSuperTypeWithRecursiveBound()
public open inner class Derived : test.RawSuperTypeWithRecursiveBound.Super<(raw) *> {
public open inner class Derived : test.RawSuperTypeWithRecursiveBound.Super<(raw) test.RawSuperTypeWithRecursiveBound.Super<*>!> {
public constructor Derived()
public open override /*1*/ fun dummy(): kotlin.Unit
public open fun foo(/*0*/ p0: kotlin.Any!): kotlin.Unit
compiler/testData/loadJava/compiledJava/signaturePropagation/RawSuperTypeWithRecursiveBoundMultipleParameters.txt
Vendored
+1 -1
View File
@@ -3,7 +3,7 @@ package test
public open class RawSuperTypeWithRecursiveBoundMultipleParameters {
public constructor RawSuperTypeWithRecursiveBoundMultipleParameters()
public open inner class Derived : test.RawSuperTypeWithRecursiveBoundMultipleParameters.Super<(raw) kotlin.Any!, (raw) *> {
public open inner class Derived : test.RawSuperTypeWithRecursiveBoundMultipleParameters.Super<(raw) kotlin.Any!, (raw) test.RawSuperTypeWithRecursiveBoundMultipleParameters.Super<*, *>!> {
public constructor Derived()
public open override /*1*/ fun dummy(): kotlin.Unit
public open fun foo(/*0*/ p0: kotlin.Any!, /*1*/ p1: kotlin.Any!): kotlin.Unit