KT-156 Fix the this<Super> syntax

This commit is contained in:
Andrey Breslav
2011-10-20 18:38:51 +04:00
parent ec6dec0d37
commit d445a09a80
2 changed files with 18 additions and 1 deletions
@@ -0,0 +1,77 @@
namespace example;
trait T {
fun foo() {}
}
open class C() {
fun bar() {}
}
class A<E>() : C(), T {
fun test() {
<!SUPER_IS_NOT_AN_EXPRESSION!>super<!>
<!SUPER_IS_NOT_AN_EXPRESSION!>super<T><!>
<!AMBIGUOUS_SUPER!>super<!>.foo()
super<T>.foo()
super<C>.bar()
super<T>@A.foo()
super<C>@A.bar()
super<<!NOT_A_SUPERTYPE!>E<!>>.bar()
super<<!NOT_A_SUPERTYPE!>E<!>>@A.bar()
super<<!NOT_A_SUPERTYPE!>Int<!>>.foo()
super<>.foo()
super<<!NOT_A_SUPERTYPE!>fun() : Unit<!>>.foo()
super<<!NOT_A_SUPERTYPE!>()<!>>.foo()
super<T><!UNRESOLVED_REFERENCE!>@B<!>.foo()
super<C><!UNRESOLVED_REFERENCE!>@B<!>.bar()
}
class B : T {
fun test() {
super<T>.foo();
super<<!NOT_A_SUPERTYPE!>C<!>>.bar()
super<C>@A.bar()
super<T>@A.foo()
super<T>@B.foo()
super<<!NOT_A_SUPERTYPE!>C<!>>@B.foo()
super.foo()
<!SUPER_IS_NOT_AN_EXPRESSION!>super<!>
<!SUPER_IS_NOT_AN_EXPRESSION!>super<T><!>
}
}
}
fun foo() {
<!SUPER_IS_NOT_AN_EXPRESSION!>super<!>
super.foo()
super<Nothing>.foo()
}
trait G<T> {
fun foo() {}
}
class CG : G<Int> {
fun test() {
super<G>.foo() // OK
super<G<!TYPE_ARGUMENTS_REDUNDANT_IN_SUPER_QUALIFIER!><Int><!>>.foo() // Warning
super<<!NOT_A_SUPERTYPE!>G<<!UNRESOLVED_REFERENCE!>E<!>><!>>.foo() // Error
super<<!NOT_A_SUPERTYPE!>G<String><!>>.foo() // Error
}
}
// The case when no supertype is resolved
class ERROR<E>() : <!UNRESOLVED_REFERENCE!>UR<!> {
fun test() {
super.<!UNRESOLVED_REFERENCE!>foo<!>()
}
}
// No supertype at all
class A1 {
fun test() {
super.equals(null)
}
}