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Gradual migration of operator 'mod' to 'rem'

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- Introduce new 'rem' operator convention
 - Prefer 'rem()' to 'mod()' when both are available, even if mod() is a
   member, and rem() -- an extension
 - Place operator 'rem' under the language feature
This commit is contained in:
Mikhail Zarechenskiy
2016-12-05 22:42:16 +03:00
parent 2df9daab1f
commit 97ca51381a
29 changed files with 528 additions and 28 deletions
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compiler/testData/diagnostics/tests/operatorRem/operatorRem.txt
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+19
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package
public fun baz(): kotlin.Unit
public final class Bar {
public constructor Bar()
public open override /*1*/ /*fake_override*/ fun equals(/*0*/ other: kotlin.Any?): kotlin.Boolean
public open override /*1*/ /*fake_override*/ fun hashCode(): kotlin.Int
public final operator fun remAssign(/*0*/ x: kotlin.Int): kotlin.Unit
public open override /*1*/ /*fake_override*/ fun toString(): kotlin.String
}
public final class Foo {
public constructor Foo()
public open override /*1*/ /*fake_override*/ fun equals(/*0*/ other: kotlin.Any?): kotlin.Boolean
public open override /*1*/ /*fake_override*/ fun hashCode(): kotlin.Int
public final operator fun rem(/*0*/ x: kotlin.Int): Foo
public open override /*1*/ /*fake_override*/ fun toString(): kotlin.String
}