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Use more efficient file type check (avoid identifying file type by file)

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Dmitry Jemerov
2018-03-28 17:01:50 +02:00
parent 85ebe97597
commit 9516c638ea
1 changed files with 2 additions and 1 deletions
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idea/idea-analysis/src/org/jetbrains/kotlin/idea/util/ProjectRootsUtil.kt
+2 -1
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@@ -10,6 +10,7 @@ import com.intellij.ide.highlighter.JavaClassFileType
import com.intellij.injected.editor.VirtualFileWindow import com.intellij.injected.editor.VirtualFileWindow
import com.intellij.openapi.extensions.ExtensionPointName import com.intellij.openapi.extensions.ExtensionPointName
import com.intellij.openapi.fileTypes.FileType import com.intellij.openapi.fileTypes.FileType
import com.intellij.openapi.fileTypes.FileTypeManager
import com.intellij.openapi.module.Module import com.intellij.openapi.module.Module
import com.intellij.openapi.module.ModuleUtilCore import com.intellij.openapi.module.ModuleUtilCore
import com.intellij.openapi.project.Project import com.intellij.openapi.project.Project
@@ -65,7 +66,7 @@ object ProjectRootsUtil {
if (!includeLibraryClasses && !includeLibrarySource) return false if (!includeLibraryClasses && !includeLibrarySource) return false
// NOTE: the following is a workaround for cases when class files are under library source roots and source files are under class roots // NOTE: the following is a workaround for cases when class files are under library source roots and source files are under class roots
val fileType = file.fileType val fileType = FileTypeManager.getInstance().getFileTypeByFileName(file.name)
val canContainClassFiles = fileType == ArchiveFileType.INSTANCE || file.isDirectory val canContainClassFiles = fileType == ArchiveFileType.INSTANCE || file.isDirectory
val isBinary = fileType.isKotlinBinary() val isBinary = fileType.isKotlinBinary()