Generate bridges for trait implementations properly

The intent was to keep the bridge codegen model as simple as possible: we
should be able to figure out all necessary bridges only by a minimal interface
that FunctionHandle provides (isAbstract, isDeclaration, getOverridden)

Add different tests for bridges

 #KT-318 Obsolete
This commit is contained in:
Alexander Udalov
2014-04-07 22:29:00 +04:00
parent 4a12ea9bda
commit 79e7ee91e4
14 changed files with 289 additions and 79 deletions
+72 -7
View File
@@ -16,8 +16,12 @@
package org.jetbrains.jet.codegen.bridges
import org.jetbrains.jet.lang.descriptors.FunctionDescriptor
import org.jetbrains.jet.lang.descriptors.Modality
import org.jetbrains.jet.lang.descriptors.*
import org.jetbrains.jet.lang.resolve.DescriptorUtils
import org.jetbrains.jet.lang.resolve.OverridingUtil
import org.jetbrains.jet.lang.resolve.calls.CallResolverUtil
import org.jetbrains.jet.lang.types.TypeUtils
import java.util.LinkedHashSet
public fun <Signature> generateBridgesForFunctionDescriptor(
descriptor: FunctionDescriptor,
@@ -26,11 +30,72 @@ public fun <Signature> generateBridgesForFunctionDescriptor(
return generateBridges(DescriptorBasedFunctionHandle(descriptor), { signature(it.descriptor) })
}
/**
* An implementation of FunctionHandle based on descriptors.
*
* This implementation workarounds a minor inconvenience in descriptor hierarchy regarding traits with implementations.
* Consider the following hierarchy:
*
* trait A { fun foo() = 42 }
* class B : A
*
* In terms of descriptors, we'll have a declaration in trait A with modality=OPEN and a fake override in class B with modality=OPEN.
* For the purposes of bridge generation though, it's much easier to "move" all implementations out of traits into their child classes,
* i.e. treat the function in A as a declaration with modality=ABSTRACT and a function in B as a _declaration_ with modality=OPEN.
*
* This provides us with the nice invariant that all implementations (concrete declarations) are always in classes. This means we _always_
* can generate a bridge near an implementation (of course, in case it has a super-declaration with a different signature). Ultimately this
* eases the process of determining what bridges are already generated in our supertypes and need to be inherited, not regenerated.
*/
private data class DescriptorBasedFunctionHandle(val descriptor: FunctionDescriptor) : FunctionHandle {
override val isDeclaration: Boolean = descriptor.getKind().isReal()
override val isAbstract: Boolean = descriptor.getModality() == Modality.ABSTRACT
private val _overridden = descriptor.getOverriddenDescriptors().map { DescriptorBasedFunctionHandle(it.getOriginal()) }
override fun getOverridden(): Iterable<FunctionHandle> {
return descriptor.getOverriddenDescriptors().map { DescriptorBasedFunctionHandle(it.getOriginal()) }
}
override val isDeclaration: Boolean =
descriptor.getKind().isReal() ||
findTraitImplementation(descriptor) != null
override val isAbstract: Boolean =
descriptor.getModality() == Modality.ABSTRACT ||
DescriptorUtils.isTrait(descriptor.getContainingDeclaration())
override fun getOverridden() = _overridden
}
/**
* Given a fake override in a class, returns an overridden declaration with implementation in trait, such that a method delegating to that
* trait implementation should be generated into the class containing the fake override; or null if the given function is not a fake
* override of any trait implementation or such method was already generated into some superclass
*/
public fun findTraitImplementation(descriptor: CallableMemberDescriptor): CallableMemberDescriptor? {
if (descriptor.getKind().isReal()) return null
if (CallResolverUtil.isOrOverridesSynthesized(descriptor)) return null
// TODO: this logic is quite common for bridge generation, find a way to abstract it to a single place
// TODO: don't use filterOutOverridden() here, it's an internal front-end utility (see its implementation)
val overriddenDeclarations = OverridingUtil.getOverriddenDeclarations(descriptor)
val filteredOverriddenDeclarations = OverridingUtil.filterOutOverridden(LinkedHashSet(overriddenDeclarations))
var implementation: CallableMemberDescriptor? = null
for (overriddenDeclaration in filteredOverriddenDeclarations) {
if (DescriptorUtils.isTrait(overriddenDeclaration.getContainingDeclaration()) && overriddenDeclaration.getModality() != Modality.ABSTRACT) {
assert(implementation == null) { "Ambiguous overridden declaration: $descriptor" }
implementation = overriddenDeclaration
}
}
if (implementation == null) {
return null
}
// If this implementation is already generated into one of the superclasses, we need not generate it again, it'll be inherited
val containingClass = descriptor.getContainingDeclaration() as ClassDescriptor
val implClassType = implementation!!.getExpectedThisObject()!!.getType()
for (supertype in containingClass.getDefaultType().getConstructor().getSupertypes()) {
if (!DescriptorUtils.isTrait(supertype.getConstructor().getDeclarationDescriptor()!!) &&
TypeUtils.getAllSupertypes(supertype).contains(implClassType)) {
return null
}
}
return implementation
}