Resolve unaryPlus as plus with error.
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@@ -2,4 +2,5 @@ Function call (10: 17) A(0) + A(1) + 2
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Function call (11: 20) A(0) plus A(1) plus 2
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Function call (12: 20) A(0).plus(A(1).plus(2))
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Function call (15: 7) a += 1
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Function call (6: 30) fun plus(a: A): A = this + a.n
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Function call (6: 30) fun plus(a: A): A = this + a.n
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Unclassified usage (18: 5) +A(0)
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