Properly find invoke method on default lambda inlining

In general case parameter type could differ from actual default lambda type.
  E.g.: fun inlineFun(s: (Child) -> Base = { a: Base -> a as Child}),
  where type of default lambda is '(Base) -> Child'.
  In such case we should find somehow actual invoke method in bytecode knowing
  only name, number of parameters and that's actual invoke is non-synthetic
  regardless of bridge one.

  #KT-21946 Fixed

compiler/testData/codegen/boxInline/defaultValues/lambdaInlining/kt26636.kt

@@ -0,0 +1,25 @@
+// TARGET_BACKEND: JVM
+// IGNORE_BACKEND: JVM_IR
+// WITH_RUNTIME
+// FILE: 1.kt
+// SKIP_INLINE_CHECK_IN: enumOrThrow$default
+package test
+
+enum class TarEnum {
+    OK
+}
+inline fun <reified T : Enum<T>> String?.enumOrNull(): T? {
+    this ?: return null
+    return enumValues<T>().firstOrNull { it.name == this }
+}
+
+inline fun <reified T : Enum<T>> String?.enumOrThrow(handleNull: () -> Throwable = { IllegalArgumentException("Enum type ${T::class.java} not contain value=$this") }): T {
+    return this.enumOrNull<T>() ?: throw handleNull()
+}
+
+// FILE: 2.kt
+import test.*
+
+fun box(): String {
+    return "OK".enumOrThrow<TarEnum>()!!.name
+}