Properly find invoke method on default lambda inlining

In general case parameter type could differ from actual default lambda type.
  E.g.: fun inlineFun(s: (Child) -> Base = { a: Base -> a as Child}),
  where type of default lambda is '(Base) -> Child'.
  In such case we should find somehow actual invoke method in bytecode knowing
  only name, number of parameters and that's actual invoke is non-synthetic
  regardless of bridge one.

  #KT-21946 Fixed
This commit is contained in:
Mikhael Bogdanov
2018-12-27 15:03:40 +01:00
parent 3040a2b145
commit 6bf70a5dd2
14 changed files with 332 additions and 18 deletions
@@ -0,0 +1,21 @@
// IGNORE_BACKEND: JVM_IR
// FILE: 1.kt
// NO_CHECK_LAMBDA_INLINING
package test
interface Call {
fun run(): String
}
inline fun test(p: String, s: () -> Call = {
object : Call {
override fun run() = p
}
}) = s()
// FILE: 2.kt
import test.*
fun box(): String {
return test("OK").run()
}