Properly find invoke method on default lambda inlining

In general case parameter type could differ from actual default lambda type.
  E.g.: fun inlineFun(s: (Child) -> Base = { a: Base -> a as Child}),
  where type of default lambda is '(Base) -> Child'.
  In such case we should find somehow actual invoke method in bytecode knowing
  only name, number of parameters and that's actual invoke is non-synthetic
  regardless of bridge one.

  #KT-21946 Fixed

compiler/testData/codegen/boxInline/defaultValues/lambdaInlining/callableReferences/differentInvokeSignature.kt

@@ -0,0 +1,22 @@
+// IGNORE_BACKEND: JVM_IR
+// FILE: 1.kt
+// SKIP_INLINE_CHECK_IN: inlineFun$default
+package test
+
+open class Base
+
+class Child(val value: String) : Base()
+
+fun foo(a: Base): Child = a as Child
+
+
+inline fun inlineFun(s: (Child) -> Base = ::foo): Base {
+    return s(Child("OK"))
+}
+
+// FILE: 2.kt
+import test.*
+
+fun box(): String {
+    return (inlineFun() as Child).value
+}

compiler/testData/codegen/boxInline/defaultValues/lambdaInlining/callableReferences/differentInvokeSignature2.kt

@@ -0,0 +1,17 @@
+// IGNORE_BACKEND: JVM_IR
+// FILE: 1.kt
+// SKIP_INLINE_CHECK_IN: inlineFun$default
+package test
+
+fun foo(a: Number): String = "OK"
+
+inline fun inlineFun(s: (Double) -> String = ::foo): String {
+    return s(1.0)
+}
+
+// FILE: 2.kt
+import test.*
+
+fun box(): String {
+    return inlineFun()
+}