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Don't allow to use own members when resolve super constructor call in (companion) object

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Zalim Bashorov
2015-12-14 18:45:17 +03:00
parent e9ea4cc953
commit 69c2668530
6 changed files with 114 additions and 1 deletions
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compiler/testData/diagnostics/tests/scopes/classHeader/objectSuperConstructorArguments.txt
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+24
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@@ -0,0 +1,24 @@
package
public object A : S {
private constructor A()
public final override /*1*/ /*fake_override*/ val a: kotlin.Any
public final override /*1*/ /*fake_override*/ val b: kotlin.Any
public final override /*1*/ /*fake_override*/ val c: kotlin.Any
public final val prop1: kotlin.Int = 1
public final val prop2: kotlin.Int
public open override /*1*/ /*fake_override*/ fun equals(/*0*/ other: kotlin.Any?): kotlin.Boolean
public final fun func(): kotlin.Unit
public open override /*1*/ /*fake_override*/ fun hashCode(): kotlin.Int
public open override /*1*/ /*fake_override*/ fun toString(): kotlin.String
}
public open class S {
public constructor S(/*0*/ a: kotlin.Any, /*1*/ b: kotlin.Any, /*2*/ c: kotlin.Any)
public final val a: kotlin.Any
public final val b: kotlin.Any
public final val c: kotlin.Any
public open override /*1*/ /*fake_override*/ fun equals(/*0*/ other: kotlin.Any?): kotlin.Boolean
public open override /*1*/ /*fake_override*/ fun hashCode(): kotlin.Int
public open override /*1*/ /*fake_override*/ fun toString(): kotlin.String
}