Java 8 rules for method overrides:

- base class method wins against a (default) interface method,
so an abstract base class method should always be implemented
in a derived class;

- interface methods clash regardless of abstract/default
with possibly undefined behavior at run-time,
so a class or interface should always define its own method
for methods inherited from multiple interfaces and not from base class;

- meaningful diagnostics for class inheriting conflicting JVM signatures.
Since no override will happen under Java 8 rules,
ACCIDENTAL_OVERRIDE is misleading for this case;

- update testData.
This commit is contained in:
Dmitry Petrov
2015-10-07 14:43:39 +03:00
parent 82c0265cb3
commit 5d9ee7efee
46 changed files with 381 additions and 212 deletions
@@ -9,7 +9,7 @@ open <!ABSTRACT_MEMBER_NOT_IMPLEMENTED!>class Br<!>(<!UNUSED_PARAMETER!>t<!> : T
}
<!ABSTRACT_MEMBER_NOT_IMPLEMENTED!>class Br3<!>(t : T) : Br(t) {
<!ABSTRACT_CLASS_MEMBER_NOT_IMPLEMENTED!>class Br3<!>(t : T) : Br(t) {
}
@@ -35,4 +35,4 @@ open class GC1(g : G<Int>) : G<Int> by g {
open class GC2(g : G<Int>) : GC1(g) {
}
}
@@ -14,6 +14,6 @@ interface TwoImpl : Two {
public override fun foo() = 2
}
<!MANY_IMPL_MEMBER_NOT_IMPLEMENTED!>class Test1<!>() : TwoImpl, OneImpl {}
<!MANY_INTERFACES_MEMBER_NOT_IMPLEMENTED!>class Test1<!>() : TwoImpl, OneImpl {}
class Test2(a : One) : One by a, Two {}
<!MANY_IMPL_MEMBER_NOT_IMPLEMENTED!>class Test3<!>(a : One, b : Two) : Two by b, One by a {}