Convert to expression body: insert new-line after = for long lines

idea/testData/refactoring/extractFunction/basic/callableReferenceSelector.kt.after

@@ -10,6 +10,7 @@ class Foo {
             arguments = map(arg)
         }
 
-        private fun map(arg: String) = mapOf(Foo::arguments.name to arg)
+        private fun map(arg: String) =
+                mapOf(Foo::arguments.name to arg)
     }
 }

idea/testData/refactoring/extractFunction/parameters/capturedFunctions/localExtensionFunChainedCalls.kt.after

@@ -13,4 +13,5 @@ fun foo(n: Int): Int {
     return i(n, Int::bar1, Int::bar2)
 }
 
-private fun i(n: Int, bar1: Int.(m: Int) -> Int, bar2: Int.(m: Int) -> Int) = n.bar1(n + 1).bar2(n + 2)
+private fun i(n: Int, bar1: Int.(m: Int) -> Int, bar2: Int.(m: Int) -> Int) =
+        n.bar1(n + 1).bar2(n + 2)

idea/testData/refactoring/extractFunction/typeParameters/typeParametersAndConstraintsCombined1.kt.after

@@ -17,4 +17,5 @@ class A<T: Data>(val t: T) where T: DataEx {
     }
 }
 
-private fun <T : Data, U : Data, V : Data> i(a: A<T>, b: A<T>.B<U>, v: V) where T : DataEx, U : DataExEx, V : DataEx = a.t.x + b.u.x + v.x
+private fun <T : Data, U : Data, V : Data> i(a: A<T>, b: A<T>.B<U>, v: V) where T : DataEx, U : DataExEx, V : DataEx =
+        a.t.x + b.u.x + v.x