Quick fix for applying spread operator where vararg is expected #KT-6824 Fixed

This commit is contained in:
shiraji
2016-12-27 01:35:18 +09:00
committed by Mikhail Glukhikh
parent 6ae4b42164
commit 44e69d8adc
15 changed files with 201 additions and 7 deletions
@@ -0,0 +1,5 @@
// "Change 'array' to '*array'" "true"
fun foo(a: String, vararg x: String, b: Int) {}
fun bar(array: Array<String>) = foo("aaa", array<caret>, b = 1)