Convert reference to lambda: fix it works correctly when referenced function has default argument

#KT-17222 Fixed
#KT-24138 Fixed
#KT-39532

idea/testData/intentions/convertReferenceToLambda/referencedFunctionWithDefaultArugment.kt

@@ -0,0 +1,7 @@
+fun test() {
+    foo1(<caret>::convert2)
+}
+
+fun foo1(convert: (Int) -> Unit) {}
+
+fun convert2(i: Int, j: Int = 0) {}

idea/testData/intentions/convertReferenceToLambda/referencedFunctionWithDefaultArugment.kt.after

@@ -0,0 +1,7 @@
+fun test() {
+    foo1 { convert2(it) }
+}
+
+fun foo1(convert: (Int) -> Unit) {}
+
+fun convert2(i: Int, j: Int = 0) {}

idea/testData/intentions/convertReferenceToLambda/referencedFunctionWithDefaultArugment2.kt

@@ -0,0 +1,7 @@
+fun test() {
+    foo2(<caret>::convert3)
+}
+
+fun foo2(convert: (Int, Int) -> Unit) {}
+
+fun convert3(i: Int, j: Int, k: Int = 0) {}

idea/testData/intentions/convertReferenceToLambda/referencedFunctionWithDefaultArugment2.kt.after

@@ -0,0 +1,7 @@
+fun test() {
+    foo2 { i, j -> convert3(i, j) }
+}
+
+fun foo2(convert: (Int, Int) -> Unit) {}
+
+fun convert3(i: Int, j: Int, k: Int = 0) {}

idea/testData/intentions/convertReferenceToLambda/referencedFunctionWithDefaultArugment3.kt

@@ -0,0 +1,7 @@
+fun test() {
+    bar(<caret>Int::foo)
+}
+
+fun Int.foo(x: Int, y: Int = 42) = x + y
+
+fun bar(f: (Int, Int) -> Int) {}

idea/testData/intentions/convertReferenceToLambda/referencedFunctionWithDefaultArugment3.kt.after

@@ -0,0 +1,7 @@
+fun test() {
+    bar { i, x -> i.foo(x) }
+}
+
+fun Int.foo(x: Int, y: Int = 42) = x + y
+
+fun bar(f: (Int, Int) -> Int) {}