Convert lambda to reference: use fully qualified type names if needed #KT-13438 Fixed

(cherry picked from commit e2e761e)

idea/testData/intentions/convertLambdaToReference/fqNameForReceiver.kt

@@ -0,0 +1,13 @@
+class Foo {
+    class Bar {
+        fun foo() {}
+    }
+}
+
+class Bar {
+    fun foo() {}
+}
+
+fun use() {
+    val f: (Foo.Bar) -> Unit = { <caret>it.foo() }
+}

idea/testData/intentions/convertLambdaToReference/fqNameForReceiver.kt.after

@@ -0,0 +1,13 @@
+class Foo {
+    class Bar {
+        fun foo() {}
+    }
+}
+
+class Bar {
+    fun foo() {}
+}
+
+fun use() {
+    val f: (Foo.Bar) -> Unit = Foo.Bar::foo
+}