When checking overrides, compare methods structurally

Because they may come from different copies of the same class from different modules
This commit is contained in:
Andrey Breslav
2014-05-29 17:41:46 +04:00
parent 5a864dbc62
commit 204fa76691
27 changed files with 1158 additions and 5 deletions
@@ -0,0 +1,31 @@
// MODULE: m1
// FILE: x.kt
package p
public trait Base {
public fun foo() {}
}
public trait A : Base {
override fun foo() {}
}
public trait C : A
// MODULE: m2
// FILE: x.kt
package p
public trait Base {
public fun foo() {}
}
public trait B : Base
// MODULE: m3(m1, m2)
// FILE: x.kt
import p.*
class Foo: C, B
@@ -0,0 +1,26 @@
// MODULE: m1
// FILE: x.kt
package p
public trait Base {
public fun foo() {}
}
public trait A : Base
// MODULE: m2
// FILE: x.kt
package p
public trait Base {
public fun foo() {}
}
public trait B : Base
// MODULE: m3(m1, m2)
// FILE: x.kt
import p.*
class Foo: A, B
@@ -0,0 +1,29 @@
// MODULE: m1
// FILE: x.kt
package p
public trait Base {
public fun <T> foo(t: Array<T>) {}
}
public trait A : Base
// MODULE: m2
// FILE: x.kt
package p
public trait Base {
public fun <T: Base> foo(t: Array<T>) {}
}
public trait B : Base
// MODULE: m3(m1, m2)
// FILE: x.kt
import p.*
class Foo: A, B {
override fun <T> foo(t: Array<T>) {}
override fun <T: Base> foo(t: Array<T>) {}
}
@@ -0,0 +1,26 @@
// MODULE: m1
// FILE: x.kt
package p
public trait Base<T> {
public fun foo(t: T) {}
}
public trait A<T> : Base<T>
// MODULE: m2
// FILE: x.kt
package p
public trait Base<T> {
public fun foo(t: T) {}
}
public trait B : Base<String>
// MODULE: m3(m1, m2)
// FILE: x.kt
import p.*
class Foo: A<String>, B