Convert reference to lambda: handle special case of extension functional type #KT-14985 Fixed

idea/testData/intentions/convertReferenceToLambda/apply.kt

@@ -0,0 +1,7 @@
+// WITH_RUNTIME
+
+class My {
+    fun foo() {}
+}
+
+val x = My().apply(<caret>My::foo)

idea/testData/intentions/convertReferenceToLambda/apply.kt.after

@@ -0,0 +1,7 @@
+// WITH_RUNTIME
+
+class My {
+    fun foo() {}
+}
+
+val x = My().apply { foo() }

idea/testData/intentions/convertReferenceToLambda/extensionFunctionalType.kt

@@ -0,0 +1,8 @@
+class My {
+    fun foo(a: Int, b: String) = "$b$a"
+
+}
+
+fun baz(f: My.(Int, String) -> String) = My().f(42, "")
+
+val x = baz(<caret>My::foo)

idea/testData/intentions/convertReferenceToLambda/extensionFunctionalType.kt.after

@@ -0,0 +1,8 @@
+class My {
+    fun foo(a: Int, b: String) = "$b$a"
+
+}
+
+fun baz(f: My.(Int, String) -> String) = My().f(42, "")
+
+val x = baz { a, b -> foo(a, b) }