[O] Use max min_dur * 8 as max_dur

This commit is contained in:
2024-12-10 06:51:01 -05:00
parent 1b7e347de0
commit 8b51af821f
2 changed files with 4 additions and 3 deletions
+1 -1
View File
@@ -1,6 +1,6 @@
from __future__ import annotations from __future__ import annotations
__version__ = "1.0.28" __version__ = "1.0.29"
import time import time
import logging import logging
+3 -2
View File
@@ -44,9 +44,10 @@ PetiteVue.createApp({
d: { logs: [] }, // timestamp, duration, start_block, end_block, bad_blocks d: { logs: [] }, // timestamp, duration, start_block, end_block, bad_blocks
max_dur: 0, min_dur: 0, hover: null, firs: null, last: null, max_dur: 0, min_dur: 0, hover: null, firs: null, last: null,
onInit() { onInit() {
this.max_dur = Math.max(...this.d.logs.map(l => l.duration))
this.min_dur = Math.min(...this.d.logs.map(l => l.duration)) this.min_dur = Math.min(...this.d.logs.map(l => l.duration))
this.max_dur = Math.min(this.max_dur, this.min_dur * 8) // this.max_dur = Math.max(...this.d.logs.map(l => l.duration))
// this.max_dur = Math.min(this.max_dur, this.min_dur * 8)
this.max_dur = this.min_dur * 8
console.log(`Min duration: ${this.min_dur}, Max duration: ${this.max_dur}`) console.log(`Min duration: ${this.min_dur}, Max duration: ${this.max_dur}`)
this.first = this.d.logs[0] this.first = this.d.logs[0]
this.last = this.d.logs[this.d.logs.length - 1] this.last = this.d.logs[this.d.logs.length - 1]