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[+] A4 P4.3

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Hykilpikonna
2021-11-09 23:13:45 -05:00
parent 99720e73e2
commit 59c7925168
1 changed files with 2 additions and 5 deletions
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assignments/a4/a4_part4.py
+2 -5
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@@ -122,7 +122,7 @@ def grid_break(ciphertext: str, candidates: set[str]) -> set[int]:
# Since grid[row][col] = list[row * num_cols + col], # Since grid[row][col] = list[row * num_cols + col],
# The final index of a letter is (i % k * cols + i // k) # The final index of a letter is (i % k * cols + i // k)
# #
# We first filter only possible k, and then filter for messages where only the candidates exists # We first filter only possible k, then filter for messages where only the candidates exists
c = ciphertext c = ciphertext
n = len(c) n = len(c)
return {k for k in range(1, n) if n % k == 0 and return {k for k in range(1, n) if n % k == 0 and
@@ -138,10 +138,7 @@ def run_example_break(ciphertext_file: str, candidates: set[str]) -> list[str]:
with open(ciphertext_file, encoding='utf-8') as f: with open(ciphertext_file, encoding='utf-8') as f:
ciphertext = f.read() ciphertext = f.read()
# (Not to be handed in) Try completing this function by calling grid_break and returning a return [grid_decrypt(k, ciphertext) for k in grid_break(ciphertext, candidates)]
# list of the possible plaintext messages.
return [ciphertext] + list(candidates) # This is a dummy line, please replace it!
################################################################################ ################################################################################